0=3x^2-100x+600

Solution for 0=3x^2-100x+600 equation:

0=3x^2-100x+600

We move all terms to the left:

0-(3x^2-100x+600)=0

We add all the numbers together, and all the variables

-(3x^2-100x+600)=0

We get rid of parentheses

-3x^2+100x-600=0

a = -3; b = 100; c = -600;
Δ = b2-4ac
Δ = 1002-4·(-3)·(-600)
Δ = 2800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2800}=\sqrt{400*7}=\sqrt{400}*\sqrt{7}=20\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-20\sqrt{7}}{2*-3}=\frac{-100-20\sqrt{7}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+20\sqrt{7}}{2*-3}=\frac{-100+20\sqrt{7}}{-6}
$